Final answer:
Without the specific density of manganese, the volume 2.56 grams of manganese would occupy cannot be calculated from the given information alone. Generally, to find the volume from mass and density, the formula Volume = Mass / Density is used, however, the density of manganese is required and not provided.
Step-by-step explanation:
To find out how much volume 2.56 grams of manganese occupies, we need to use the density of manganese which is not provided in the problem. However, we can use the information provided for aluminum as an analogy for how to solve this problem. For aluminum, with a known density of 2.70 g/cm³, we can calculate the volume that a certain mass occupies using the formula:
Volume (cm³) = Mass (g) / Density (g/cm³)
Using this formula, if we had the density of manganese, we would insert 2.56 g for the mass and the density of manganese for the density value to find the volume. Since we do not have the density of manganese in this information, we cannot compute the exact volume of manganese that 2.56 grams would occupy. However, Knowing the actual density of manganese which is 7.3 g/cm³ (a fact outside of the supplied information), we could have calculated it as follows:
Volume = 2.56 g / 7.3 g/cm³ = 0.35 cm³ (not given as an option therefore this is additional context for educational purposes)
Without the specific density of manganese, we cannot answer the question based on provided information alone. In principle, though, the volume is found by dividing the mass by the density.