Question

A labourer is engaged for 20 days on the condition that he will receive rupees 120 each day. He works and will be fined rupees 10 for each day he is absent. If he receives rupees 1880 in all, for how many days did he remain absent?

A) 2
B) 3
C) 4
D) 5

Answer 1

The labourer was engaged to work for 20 days with a daily wage of 120 rupees and a fine of 10 rupees for each day absent. After receiving a total of 1880 rupees, a simple arithmetic calculation shows that he was absent for 4 days.

Step-by-step explanation:

The question is related to a simple arithmetic problem about wages and fines, which we can solve using basic algebra. The labourer is supposed to work for 20 days and gets paid 120 rupees per day. However, for each day absent, he is fined 10 rupees. We are told that the labourer received a total of 1880 rupees.

Let's assume that the number of days the labourer was absent is x. The total amount he would have earned without any absences is 20 days * 120 rupees/day = 2400 rupees. Since he was absent for x days, he would not earn 120 rupees for each of those days and also be fined 10 rupees for each of those days. Therefore, the equation to calculate his earnings is:

2400 - (120 + 10) * x = 1880

Solving this equation:

1. 2400 - 130x = 1880
2. 2400 - 1880 = 130x
3. 520 = 130x
4. x = 520 / 130
5. x = 4

So, the labourer was absent for 4 days. The correct answer is C) 4.