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A person who is standing on a ledge throws a rock into the air. The rock reaches a maximum height of 676 feet

above the ground after 1.5 seconds.
If the rock hits the ground below the ledge 8 seconds after it is thrown, which quadratic function can be used to find
the height of the rock above the ground t seconds after it is thrown?
A. H(t) = -9/16(t-8)^2+676
B. H(t)= -9/16(t+8)^2+676
C. H(t)= -16(t-1.5)^2+676
D. H(t)= -16(t+1.5)^2+676

User Koorchik
by
8.4k points

1 Answer

5 votes
B hope it’s right I’m not sure
User Charlie Roberts
by
7.8k points
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