Question

A stone is allowed to fall from a tower of height 200 m and at thesame time another stone is projected vertically upwards from theground at a velocity of 50 m/s. Calculate when and where the stoneswill meet. (Take a =10m/s^2)​.

Answer 1

The stones will meet after a time of 2t and at a height of 200m above the ground.

Step-by-step explanation:

We can use the equations of motion to determine when and where the two stones will meet. Let's start by calculating when they will meet. The stone dropped from the tower will take time t to reach the ground, and the stone projected upwards will also take time t to reach its highest point and start coming down. The total time taken by the stones to meet will be 2t.

Now, let's calculate where they will meet. The stone dropped from the tower will travel a distance of 200 m. The stone projected upwards will also travel a distance of 200 m in the opposite direction. Therefore, they will meet at a height of 200 m above the ground.

So, the stones will meet after a time of 2t and at a height of 200 m above the ground.