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We found an account that will gain 12% interest compounded monthly. We plan on opening the account with $250. We are going to deposit the same amount of money into the account every month for the next 3 years. If in three years we have a balance of $1750.45, how much were we putting in every month?

A. $31.24
B. $36.34
C. $37.93
D. $32.33"

User Sagism
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1 Answer

5 votes

Final answer:

To find out how much money was being deposited into the account every month, we need to use the formula for compound interest. Substituting the given values into the formula, we find that the amount being deposited every month is approximately $37.93.

Step-by-step explanation:

To find out how much money was being deposited into the account every month, we need to use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:

A is the final balance after t years

P is the initial principal (amount deposited)

r is the annual interest rate (written as a decimal)

n is the number of times interest is compounded per year

t is the time in years

In this case, we have:

A = $1750.45

P = $250

r = 12% or 0.12

n = 12 (compounded monthly)

t = 3 years

Substituting these values into the formula, we get:

$1750.45 = $250(1 + 0.12/12)^(12*3)

Simplifying further, we find:

$1750.45 = $250(1.01)^36

Dividing both sides by $250, we have:

7.0018 = (1.01)^36

Now we can solve for (1.01)^36:

(1.01)^36 ≈ 1.44033

Multiplying both sides by $250, we obtain:

7.0018 * $250 ≈ $1750.45

Therefore, the amount being deposited every month is approximately $37.93. Therefore, the answer is C. $37.93.

User Ccjmne
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