Final answer:
To find the molar ratio between 2Pb and 2PbS, you assess the subscripts in the chemical formulas. Both components have 2 moles of Pb, so the molar ratio is 2:2, which simplifies to a 1:1 ratio.
Step-by-step explanation:
To find the molar ratio between 2Pb and 2PbS, we need to understand that molar ratios are derived from the coefficients of a balanced chemical equation or from the subscripts in chemical formulas that indicate the number of atoms of each element that are present. In this case, there are no chemical equations provided, but we can look at the subscripts in the chemical formulas 2Pb and 2PbS to determine the molar ratio.
For the elemental lead, 2Pb, each atom of Pb represents one mole, so we have 2 moles of Pb. For lead sulfide, 2PbS, each formula unit of PbS consists of one mole of lead (Pb) and one mole of sulfur (S), so we have 2 moles of PbS which contains 2 moles of Pb and 2 moles of S.
The molar ratio of Pb in 2Pb : Pb in 2PbS is thus 2: 2, which simplifies to a 1:1 ratio. This means that for every one mole of Pb in elemental lead, there is one mole of Pb in lead sulfide.