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14 votes
1 poi (7) Write the equation of a line that has a slope of -5 and passes through the point (2, -13)

User Markc
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1 Answer

19 votes
19 votes

Answer:

Explanation:

The equation of a line in slope-intercept form is


y=mx+b

where m is the slope and b is the y-intercept.

Now we know that the slope is -5; therefore m = -5 and our equation becomes


y=-5x+b

Now we only need to find the y-intercept b of the line, and to do this we use the point (2, -13). Putting in x = 2 and y = -13 in the above equation gives


-13=-5(2)+b
-13=-10+b

Adding 10 to both sides gives


-13+10=b
b=-3

With the value of b in hand, we now write the equation in slope-intercept form


y=-5x-3

which is our answer!

User George Lund
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