Question

If log5 x = 4.26, what is the value of log5 5x^2??

Answer 1

`log_(5)(x) = 4.26`

`log_(5)( {5x}^(2) ) =`

`log_(5)(5) + log_(5)( {x}^(2) ) =`

`log_(5)(5) + 2 log_(5)(x) =`

`1 + 2(4.26) = 1 + 8.52 = 9.52`

Answer 2

To find the value of log5 5x^2, use the properties of logarithms to rewrite the expression and substitute the given value of log5 x.

Step-by-step explanation:

To find the value of log5 5x^2, we can use the properties of logarithms. One property states that for any base, b, log_b (a^c) is equal to c * log_b (a). Using this property, we can rewrite log5 5x^2 as 2 * log5 (5x). Since we know that log5 x = 4.26, we can substitute this value in and calculate:

1. 2 * log5 (5x)
2. 2 * 4.26
3. 8.52