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How much 10% acid solution must be mixed with a 30% acid solution to make 500 L of 15% acid solution?

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Final answer:

To make 500 L of a 15% acid solution, 375 L of a 10% acid solution should be mixed with 125 L of a 30% acid solution.

Step-by-step explanation:

To determine how much 10% acid solution must be mixed with a 30% acid solution to make 500 L of a 15% acid solution, you can use an equation based on total amounts of pure acid in the solution. Let's denote the volume of the 10% solution as x liters and the volume of the 30% solution as (500 - x) liters. The equation to represent the total acid after mixing will be:

0.10x + 0.30(500 - x) = 0.15 × 500

Now, solve for x:

0.10x + 150 - 0.30x = 75,

-0.20x = -75,

x = 375 L.

Therefore, 375 liters of the 10% acid solution should be mixed with 125 liters (500 L - 375 L) of the 30% acid solution to obtain 500 liters of a 15% acid solution.

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