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City A has a population of 2.3x10^5, and City B has a population of 1,840,000. If City C's population is five times that of City B, how many times is the population of City C compared to City A?

A) 2.3
B) 5
C) 8
D) 10

User Lpil
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Final answer:

The population of City C is 40 times that of City A, which is calculated by dividing City C's population of 9,200,000 by City A's population of 2.3 x 10^5. correct option is not mention.

Step-by-step explanation:

The student has presented a problem calculating relative populations between three cities, A, B, and C. City A has a population of 2.3 x 10^5, City B has a population of 1,840,000, and City C's population is five times that of City B. Therefore, the population of City C is 5 x 1,840,000, which equals 9,200,000. To compare the population of City C to City A, we divide the population of City C by the population of City A, which gives us 9,200,000 / (2.3 x 10^5) = 40. This means that the population of City C is 40 times the population of City A, which is not one of the options provided (A) 2.3 (B) 5 (C) 8 (D) 10).

User Sagar Damani
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