Question

A Navy jet will travel 67m/s approaching an aircraft carrier. Upon landing a hook grabs a stop wire bringing the jet to a screeching halt with an acceleration of -26.8 m/s2. How much time does the jet need to come to a stop?

Answer 1

To calculate the time it takes for the jet to stop, the equation of motion v = u + at is used, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Upon substituting the values, the jet requires 2.5 seconds to come to a stop.

Step-by-step explanation:

The question involves finding out how much time it takes for a Navy jet to come to a stop upon landing on an aircraft carrier. Given that the Navy jet has an initial velocity of 67m/s and an acceleration of -26.8 m/s2 when it catches the stop wire, we can use the equation of motion:

v = u + at

Here, v is the final velocity (which is 0 m/s since the jet comes to a stop), u is the initial velocity (67m/s), a is the acceleration (-26.8 m/s2), and t is the time we want to find.

Rearranging the equation to solve for t, we get:

t = (v - u) / a

Plugging in the given values:

t = (0 - 67) / -26.8 = 2.5 seconds

Therefore, the jet needs 2.5 seconds to come to a stop after the hook grabs the stop wire.