Question

What is the equation in standard form of the line that passes through the point (-5, 23) and has a slope of -14/5?

A) 14x + 5y = -75.
B) -14x - 5y = 75.
C) -14x + 5y = 75.
D) 14x - 5y = -75.

Answer 1

The equation in standard form of the line passing through (-5, 23) with a slope of -14/5 is 14x - 5y = -75.

Step-by-step explanation:

The equation in standard form of the line that passes through the point (-5, 23) and has a slope of -14/5 is D) 14x - 5y = -75.

To determine the equation, we can use the point-slope form of a line, which is y - y1 = m(x - x1). Plugging in the x-coordinate -5, y-coordinate 23, and slope -14/5, we get y - 23 = (-14/5)(x - (-5)).

Simplifying the equation, we get y - 23 = (-14/5)(x + 5). Multiplying both sides by 5 to eliminate the fraction, we have 5y - 115 = -14x - 70. Rearranging the equation to standard form, we get 14x - 5y = -75.