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The slope of a line is -1/3, and the point (-6, 11) lies on the line. What is the equation of the line in slope-intercept form?

A) y = -1/3x + 11
B) y = 3x - 11
C) y = -1/3x - 11
D) y = 1/3x + 11

User Rshahriar
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1 Answer

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Final answer:

The equation of the line in slope-intercept form is y = -1/3x + 9.

Step-by-step explanation:

The equation of a line in slope-intercept form is given by y = mx + b, where m represents the slope and b represents the y-intercept. We are given that the slope of the line is -1/3. Therefore, the equation of the line is of the form y = -1/3x + b. To find the value of b, we can substitute the coordinates of the given point (-6, 11) into the equation and solve for b.

Substituting the values, we get 11 = (-1/3)(-6) + b. Simplifying, we have 11 = 2 + b. Subtracting 2 from both sides, we find that b = 9.

Therefore, the equation of the line in slope-intercept form is y = -1/3x + 9.

User LTH
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