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Which of the following equations has infinitely many solutions? (EE7a)

A. 3x - 5 = -5 + 3x.
B. 2x + 3 = 5 + 3x.
C. 2x + 3 = 5 + 3x.
D. 3x 5 = -5 - 2x.

1 Answer

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Final answer:

The equation A. 3x - 5 = -5 + 3x has infinitely many solutions.

Step-by-step explanation:

To determine which equation has infinitely many solutions, we need to look for equations where the variables cancel out. Let's analyze each option:

A. 3x - 5 = -5 + 3x: Subtracting 3x from both sides, we get -5 = -5, which is true for any value of x. Therefore, this equation has infinitely many solutions.

B. 2x + 3 = 5 + 3x: Subtracting 2x from both sides, we get 3 = 5, which is false. So, this equation has no solution.

C. 2x + 3 = 5 + 3x: Subtracting 3x from both sides, we get 3 = 5, which is false. So, this equation also has no solution.

D. 3x + 5 = -5 - 2x: Combining like terms, we get 5x + 5 = -5. Subtracting 5 from both sides and dividing by 5, we get x = -2. So, this equation has only one solution.

Therefore, the equation A. 3x - 5 = -5 + 3x has infinitely many solutions.

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