Final answer:
The mass of zinc in 750.0 mL, using the density of zinc (7.140 g/cm³), is 5355000 mg.
Step-by-step explanation:
The mass of zinc present in 750.0 mL of zinc can be calculated using the density of zinc, which is 7.140 g/cm³. To convert 750.0 mL to cm³, we use the fact that 1 mL is equivalent to 1 cm³. Therefore, 750.0 mL is also 750.0 cm³.
Using the Density Formula , which is mass = density × volume, the mass in grams is:
Mass = 7.140 g/cm³ × 750.0 cm³ = 5355 g
To convert this mass into milligrams (mg), we remember that 1 g is equivalent to 1000 mg, so:
Mass in mg = 5355 g × 1000 mg/g = 5355000 mg
Therefore, the mass of zinc present in 750.0 mL of zinc is 5355000 mg.