Final answer:
The static friction force that prevents the toy chest from moving is equal to the horizontal component of the applied force, which is approximately 123.21N, calculated using the cosine of the angle at which the child is pushing. However, the correct answer is not listed among the provided options.
Step-by-step explanation:
The student is attempting to slide a 47kg toy chest across the floor by pushing with a 125N force at a 10° angle. When an object is pushed at an angle, only the horizontal component of the force contributes to moving the object. The vertical component of the force contributes to the normal force. To find the horizontal force (Fhorizontal), we use the cosine of the angle (cos(10°)) multiplied by the applied force (125N).
Fhorizontal = 125N × cos(10°) = 123.21N (approx)
Since the box does not move, the static friction force must equal the horizontal component of the applied force, hence the static friction force is approximately 123.21N. However, none of the options (A 25.7 N, B 125 N, C 11.8 N, D 5.2 N) match this answer. Therefore, the correct answer may not be provided among the options given or there might be additional context required to solve the problem as presented. The student may need to verify the options or review the question again.