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What is the solution to the equation V8x = 4 + 2x?
(A) 2/5
(B) 2/3
(C) 24
(D) 40

User Iammurtaza
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1 Answer

7 votes

Final answer:

The solution to √(8x) = 4 + 2x involves first squaring both sides and simplifying, but the resulting quadratic equation has no real solutions, indicating a potential typo in the given equation.

Step-by-step explanation:

To solve the equation √(8x) = 4 + 2x, we first square both sides to remove the square root, yielding:


8x = (4 + 2x)²


Now, expand the right side of the equation:


8x = 16 + 16x + 4x²


To solve the quadratic equation, collect all terms on one side:


4x² + 16x - 8x + 16 = 0


Combining like terms, we have:


4x² + 8x + 16 = 0


Dividing the entire equation by 4 simplifies it:


x² + 2x + 4 = 0


This is a quadratic equation, and it seems that there might have been a typo as this particular quadratic equation has no real solutions. Therefore, if we were solving √(8x) = 4 + 2x, it is likely that the actual equation was different. If it were √(8x) = 4 - 2x, squaring both sides would lead to:


8x = (4 - 2x)²


8x = 16 - 16x + 4x²


4x² + 16x - 8x - 16 = 0


4x² + 8x - 16 = 0


x² + 2x - 4 = 0


Now, using the quadratic formula, we find that the equation does have real solutions, unlike our previous case. Always double-check the initial equation for typos.

User Jaytjuh
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