Question

The current in one part of a series of circuits is 4-3i amps. The current in another part of the circuit is 6+9i amps. Add the currents together to get the total current of the circuit.

A. 10 + 6i amps
B. 2 + 6i amps
C. 10 + 6i amps
D. 2 + 6i amps

Answer 1

The total current in a series circuit with currents of 4-3i amps and 6+9i amps is the sum of the real parts and the sum of the imaginary parts, resulting in 10 + 6i amps.

Step-by-step explanation:

To find the total current in a series circuit with complex currents, you add the real parts together and the imaginary parts together separately. The currents given in the problem are 4-3i amps and 6+9i amps. To add these currents, combine the real parts (4+6) and the imaginary parts (-3i+9i) to get the total current.

The sum of the real parts is 10 and the sum of the imaginary parts is 6i.

Therefore, the total current in the circuit is 10 + 6i amps.