Question

A Navy jet will travel 67 m/s approaching an aircraft carrier. Upon landing, a hook grabs a stop wire, bringing the jet to a screeching halt with an acceleration of -26.8 m/s^2. How much time does the jet need to come to a stop?

Answer 1

It takes the Navy jet 2.5 seconds to come to a stop after the hook grabs the stop wire, using the kinematic equation v = u + at.

Step-by-step explanation:

To calculate the amount of time the jet needs to come to a stop, we can use one of the kinematic equations of motion that relates velocity, acceleration, and time. In this case, the formula is v = u + at, where:

• v is the final velocity (0 m/s because the jet comes to a stop),
• u is the initial velocity (67 m/s),
• a is the acceleration (-26.8 m/s²).

Rearrange this equation to solve for time (t), we get:

t = (v - u) / a

Plugging in the given values:

t = (0 m/s - 67 m/s) / -26.8 m/s² = 2.5 s

Therefore, it takes the jet 2.5 seconds to come to a stop after the hook grabs the stop wire.