Final answer:
The relation t=2π√(I/mg) is incorrect as it mixes elements of linear and rotational motion incorrectly without representing a standard time period formula for any physical system.
Step-by-step explanation:
The provided relation t = 2π√(I/mg) is incorrect for a couple of reasons. First, the given formula does not correctly represent the time period for any standard physical system. In physics, the time period of a simple pendulum, for example, is given by t = 2π√(l/g), where l is the length of the pendulum and g is the acceleration due to gravity. If I is intended to represent the moment of inertia, then such a relation might resemble the period of a physical pendulum or a torsional pendulum, but the formula provided mixes elements of both linear and rotational motion incorrectly and is missing key factors for either system. Therefore, the relation is not applicable in its current form. The units for the time period are in seconds, and the general relationship among torque, moment of inertia, and angular acceleration is T = Ia, where T stands for torque, I represents the moment of inertia, and a is the angular acceleration.