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Given the equation (6 - x) + (3y)i = -12 + 27i, what are the values of x and y?

A) x = 18, y = 5
B) x = 6, y = 3
C) x = 3, y = 9
D) x = 12, y = 3

1 Answer

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Final answer:

The values of x and y in the equation (6 - x) + (3y)i = -12 + 27i are x = 18 and y = 9.

Step-by-step explanation:

To solve the equation (6 - x) + (3y)i = -12 + 27i, we can equate the real and imaginary parts on both sides of the equation. The real part on the left side is 6 - x and the real part on the right side is -12. Equating them, we get 6 - x = -12. Solving for x, we find x = 18.

The imaginary part on the left side is 3y and the imaginary part on the right side is 27. Equating them, we get 3y = 27. Solving for y, we find y = 9.

Therefore, the values of x and y are x = 18 and y = 9. So, the correct answer is option A) x = 18, y = 9.

User Amir Khorsandi
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