Final answer:
The product of -4 times the square root of 11 by its conjugate is 44.
Step-by-step explanation:
To find the product of -4 times the square root of 11 by its conjugate, we will use the formula for the difference of squares. The conjugate of a number is obtained by changing the sign of the second term. So, the conjugate of the square root of 11 is -√11.
Multiplying -4√11 by its conjugate, -√11, results in (-4√11)(-√11) = 4√11(√11) = 4√11 × √11 = 4 × 11 = 44.
Therefore, when you multiply -4√11 by its conjugate, you get 44.