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Mr. Noodle throws a football with a horizontal velocity of 10 m/s. If he throws it from the top of the football stands that are 10 meters high, how far away from him will the ball land?

A) 5 meters
B) 10 meters
C) 15 meters
D) 20 meters

User Fouronnes
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1 Answer

6 votes

Final answer:

The ball will land approximately 14.3 meters away from Mr. Noodle.

Step-by-step explanation:

To determine the distance the ball will land from Mr. Noodle, we can use the equations of projectile motion. Since the ball is thrown horizontally, the only force acting on it is gravity in the vertical direction. This means that the ball's horizontal velocity will remain constant at 10 m/s throughout its flight.

Using the equation d = vt, where d is the distance, v is the velocity, and t is the time, we can calculate the time it takes for the ball to fall 10 meters. Since the initial vertical velocity is 0 m/s, the time can be found using the equation y = y0 + v0t + 0.5at^2, where y is the vertical distance, y0 is the initial vertical position, v0 is the initial vertical velocity, a is the acceleration due to gravity (-9.8 m/s^2), and t is the time. Solving this equation for t gives us t = sqrt(2y/a).

Plugging in the values, t = sqrt((2 * 10) / 9.8) = 1.43 seconds. Since the horizontal velocity is constant at 10 m/s, the distance the ball travels horizontally will be d = vt = 10 * 1.43 = 14.3 meters. Therefore, the ball will land approximately 14.3 meters away from Mr. Noodle.

User Josh Dzielak
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