Question

What is the value of the constant deceleration experienced by a rifle bullet traveling at a velocity of 330 m/s when it is fired directly into a dense material and comes to a complete stop after penetrating 30 cm into the material?

A) 2 m/s²
B) 2200 m/s²
C) 9.8 m/s²
D) 1100 m/s²

Answer 1

The deceleration experienced by a bullet coming to a stop after penetrating 30 cm into a dense material, given its initial velocity and distance traveled, is calculated to be 181,666.67 m/s². This value is not listed in the provided options, indicating a possible error in the question.

Step-by-step explanation:

To determine the value of the constant deceleration that a rifle bullet experiences when coming to a stop after entering a dense material, we can use the kinematic equation v2 = u2 + 2as, where:

• v is the final velocity (0 m/s, since the bullet stops)
• u is the initial velocity (330 m/s)
• a is the acceleration (or deceleration in this case, which we need to find)
• s is the distance traveled (30 cm or 0.3 m)

Rearranging the equation to solve for a, we get:

a = (v2 - u2)/(2s)

a = (0 - 3302)/(2 * 0.3)

a = (-109,000)/(0.6) ≈ -181,666.67 m/s2

Since deceleration is a decrease in velocity, the negative sign indicates deceleration, but we typically report deceleration as a positive value. Thus, the magnitude of the deceleration is 181,666.67 m/s2, which is not one of the given options. This might suggest a typo in the question or that the question is incorrect.