Final answer:
The student's question involves calculating the horizontal distance of projectile motion for water exiting a pipe at a 60-degree angle from level ground in the subject of physics. This is accomplished using kinematic equations after determining the initial velocity of the water.
Step-by-step explanation:
The student's question asks to calculate the horizontal distance reached by water exiting a pipe at a 60° angle from level ground, assuming negligible air resistance. This question relates to projectile motion, a topic within the field of physics, specifically involving kinematic equations and the concepts of initial velocity, launch angles, and gravity.
To solve the problem, one would first determine the speed at which the water emerges from the pipe, which can be acquired from Bernoulli's equation or other relevant fluid dynamics principles. Once the initial velocity is known, the horizontal distance (range) can be found using the projectile motion equations, considering the launch angle and the acceleration due to gravity. Since air resistance is negligible, the only force acting on the water after it exits the pipe is gravity.
As an example to the student, if the water exits the pipe with an initial velocity of v, the horizontal range R can be calculated using the formula R = (v^2 × sin(2×angle)) / g, where angle is the launch angle (in this case, 60°), and g is the acceleration due to gravity. Substituting the known values will provide the horizontal distance.