Question

The concentration of the original sulfuric acid solution is:

a. 0.238 M
b. 0.0795 M
c. 0.159 M
d. 0.2385 M

Answer 1

The final concentration of sulfuric acid in solution C is 0.2385 M, calculated by consecutive dilution steps, applying the dilution formula C1V1 = C2V2 at each step.

Step-by-step explanation:

To find the final concentration of sulfuric acid in solution C, we need to perform a series of dilution calculations. Starting with the initial concentration of sulfuric acid (0.177 M), we will follow each dilution step.

1. First dilution: The 1.50 mL of 0.177 M sulfuric acid is diluted to 10.0 mL, forming solution A.
2. Second dilution: A 10.0 mL aliquot of A is further diluted to 50.0 mL, forming solution B.
3. Third dilution: Then, 10.0 mL of solution B is diluted to 1.0000 L to give the final solution C.

To calculate concentration at each step, use the formula C1V1 = C2V2, where C is the concentration and V is the volume. By applying this formula at each step and carrying over the resultant concentration to the next, we find the final concentration in solution C to be 0.2385 M.