Final answer:
The preimage of C'(-3, -10) is C(-11, -9).
Step-by-step explanation:
The given translation is (x, y) = (x - 8, y + 1). To find the preimage of C'(-3, -10), we need to apply the translation in reverse. This means we will substitute -3 for x and -10 for y in the translation equation.
Substituting -3 for x and -10 for y, we get:
(-3, -10) = (-3 - 8, -10 + 1)
Simplifying:
(-3, -10) = (-11, -9)
Therefore, the preimage of C'(-3, -10) is C(-11, -9).