Question

In right triangle ABC, ∠M2C = 90°, cos A = 1/5. What is sin B?

A. 4/5
B. 90 - 1/5
C. 5/1

Answer 1

In a right triangle ABC, with ∠M2C = 90° and cos A = 1/5, the sin B can be found using the Pythagorean identity.

Step-by-step explanation:

In a right triangle ABC, with ∠M2C = 90° and cos A = 1/5, we can find sin B using the Pythagorean identity.

The Pythagorean identity states that sin²A + cos²A = 1.

Since ∠M2C = 90°, sin B = 1 - cos²B. Substituting the given value of cos A = 1/5, we get sin B = 1 - (1/5)² = 1 - 1/25 = 24/25.