Question

The Shoshone basin had 5000 ft of water in it at the beginning of the year. If the water flows over Shoshone Falls into the basin at a rate of 300 ft per second, write an equation to represent how much water is in the basin after n seconds.

A. y = 5000 + 300n
B. y = 300n - 5000
C. y = 5000 - 300n
D. y = 5000 / 300n

Answer 1

The equation that represents the amount of water in the basin after n seconds is y = 5000 + 300n.

Step-by-step explanation:

The equation that represents the amount of water in the basin after n seconds is y = 5000 + 300n.

The initial amount of water in the basin is 5000 ft. The water flows into the basin at a rate of 300 ft per second, so after n seconds, the additional amount of water can be calculated by multiplying the rate by the time, which is 300n. Adding this to the initial amount of water gives the equation y = 5000 + 300n. Option A, y = 5000 + 300n, is the correct equation.