Question

297 J of heat are needed to raise the temperature of aluminum from 22°C to 55°C where the specific heat of aluminum is 0.90 J/g°C. What is the mass of the aluminum?

Answer 1

The mass of the aluminum, given the specific heat of 0.90 J/g°C and the heat transfer of 297 J for a temperature change from 22°C to 55°C, is calculated to be 10 grams.

Step-by-step explanation:

To calculate the mass of the aluminum using the heat transferred, you can rearrange the heat transfer equation Q = mc∆T, where Q is the heat energy transferred, m is the mass of the substance, c is the specific heat capacity, and ∆T is the change in temperature. Given that the specific heat of aluminum is 0.90 J/g°C, and the heat transferred is 297 J, with a temperature change (∆T) from 22°C to 55°C, we can solve for the mass (m).

First, calculate the change in temperature: ∆T = 55°C - 22°C = 33°C.

Then, rearrange the formula to solve for the mass: m = Q / (c∆T).

Substitute the values: m = 297 J / (0.90 J/g°C * 33°C).

So, the mass m = 297 J / (29.7 J/g) = 10 grams.

Therefore, the mass of the aluminum is 10 grams.