Question

Beretta goes to Jupiter where ""g"" is 2.5 times that of Earth. He stands 8.3 m above the floor and drops a frog. How fast does the frog hit the floor?

Answer 1

The frog dropped by Beretta from a height of 8.3 m on Jupiter will hit the floor at approximately 20.2 m/s, calculated using the kinematic equation with Jupiter's acceleration due to gravity, which is 2.5 times Earth's.

Step-by-step explanation:

Beretta goes to Jupiter and drops a frog from a height of 8.3 m above the floor. On Earth, the acceleration due to gravity (“g”) is 9.8 m/s2, but on Jupiter, it is 2.5 times greater. To calculate how fast the frog hits the floor, we will use the kinematic equation:

v2 = u2 + 2as

Where:

• 
  
• v is the final velocity
• 
  
• u is the initial velocity (0 m/s, since the frog is dropped)
• 
  
• a is the acceleration (on Jupiter, this is 2.5 * 9.8 m/s2)
• 
  
• s is the distance (8.3 m)

After substituting the values, we have:

v2 = 0 + 2 * (2.5 * 9.8) * 8.3

Therefore, the calculation for final speed will be:

v = √(2 * 24.5 * 8.3)

v = √(406.7)

v ≈ 20.2 m/s

Thus, the frog will hit the floor at approximately 20.2 m/s on Jupiter.