Final answer:
The volume occupied by 0.53 mols of carbon dioxide gas at STP is 11.872 liters, using the molar volume of a gas at STP which is 22.4 L/mol.
Step-by-step explanation:
To determine the volume of carbon dioxide gas occupied by 0.53 mols at Standard Temperature and Pressure (STP), we can use the molar volume of a gas at STP. One mole of any ideal gas at STP occupies 22.4 L. Therefore, to find the volume of 0.53 mols of carbon dioxide at STP, we can perform the following calculation:
Volume = number of moles × molar volume at STP
Volume = 0.53 mols × 22.4 L/mol
Volume = 11.872 liters
So, 0.53 mols of carbon dioxide gas at STP occupies 11.872 liters.