Question

The Tokyo tower, known as the Skytree is 1092 feet high. If a person whose eyes are 6 feet above ground is looking at the top of the tower with an angle of 58°, how far away is the person standing from the Skytree?

Answer 1

To find the distance between the person and the Skytree, we can use trigonometry. Using the tangent function, we can solve for the distance, which is approximately 812.4 feet.

Step-by-step explanation:

To find the distance between the person and the Skytree, we can use trigonometry. We know the height of the Skytree is 1092 feet and the angle at which the person is looking is 58°. We can use the tangent function to find the distance. The tangent of an angle is equal to the opposite side divided by the adjacent side. In this case, the opposite side is the height of the Skytree and the adjacent side is the distance we are trying to find. So we have:

tan(58°) = height / distance

Plugging in the values, we get:

tan(58°) = 1092 / distance

Now we can solve for distance:

distance = 1092 / tan(58°)

Using a calculator, we find that the distance is approximately 812.4 feet.