Question

Hi, can you help me answer this question, please, thank you!

Answer 1

Given,

The mean of the test score is 1013.

The standard deviation of the test score is 125.

The percentage of cutoff is 9%.

The z score at 9% is,

`Z=1.35`

The z score is calculated as,

Substituting the value of z, mean and standard deviation then,

`\begin{gathered} 1.35=(X-1013)/(125) \\ 168.75=X-1013 \\ X=1182 \end{gathered}`

Hence, the cutoff for the top 9% is 1182.