Question

Two planes flew between two ciriew at speed of 200 miles per hour and 260mioes per hour respectively. If the slower plane required one and a half hours longer,how far apart are the cities?

Answer 1

The cities are 780 miles apart. This is determined by setting up equations based on the speeds of 200 mph and 260 mph and the additional 1.5 hours taken by the slower plane, and then solving for distance.

Step-by-step explanation:

To find how far apart the cities are, let's use the information that two planes flew between two cities at speeds of 200 miles per hour and 260 miles per hour respectively, and that the slower plane took one and a half hours longer to cover the same distance. We can set up an equation using the fact that distance is equal to speed multiplied by time (D = S x T).

Let the time taken by the faster plane be t hours. Then the slower plane took t + 1.5 hours. We can set up two equations based on the speeds:

• For the faster plane: D = 260t
• For the slower plane: D = 200(t + 1.5)

Since both planes cover the same distance, we can set the equations equal to each other:

260t = 200(t + 1.5)

Solving for t, we get:

t = 3 hours

Now we can find the distance by substituting t back into either of the original equations. Using the faster plane's equation:

D = 260 x 3 = 780 miles

Therefore, the cities are 780 miles apart.