Final answer:
To find the number of moles in 321 g of LiCl, you divide the mass of LiCl by its molecular mass (42.39 g/mol), which gives approximately 7.57 moles.
Step-by-step explanation:
To calculate how many moles are represented by 321 g of LiCl, we first need to know the molecular mass of LiCl. Lithium (Li) has an atomic mass of approximately 6.94 g/mol, and chlorine (Cl) has an atomic mass of approximately 35.45 g/mol. Therefore, the molecular mass of LiCl (6.94 g/mol + 35.45 g/mol) is about 42.39 g/mol.
With the molecular mass of LiCl, we can use the following equation to determine the number of moles: number of moles (n) = mass (m) / molecular mass (M).
Substituting the given values into the equation, we get
n = 321 g / 42.39 g/mol.
Calculating this gives us n ≈ 7.57 mol. Therefore, 321 g of LiCl is equivalent to approximately 7.57 moles.