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Stress = 2 x 10^7 N/m². What is the tension (tension = ?) when the area is 1.5 mm²?

User DibsyJr
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1 Answer

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Final answer:

The tension in the material when the area is 1.5 mm² and the stress is 2 x 10^7 N/m² is calculated to be 30 Newtons.

Step-by-step explanation:

The student is asking about calculating tension in a material given the stress and the cross-sectional area. The formula to find tension (T) is:

T = stress × area

We are given that the stress is 2 x 10^7 N/m², and the area is 1.5 mm². First, we need to convert the area from mm² to m²:

1.5 mm² = 1.5 x 10^-6 m²

Now, we can calculate the tension as follows:

T = (2 x 10^7 N/m²) × (1.5 x 10^-6 m²)

T = 30 N

Therefore, the tension in the material with a cross-sectional area of 1.5 mm² and stress of 2 x 10^7 N/m² is 30 Newtons.

User Syed Amir Ali
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