Question

Given the equation y = 3x² - 5 + 0, find the Axis of Symmetry and Vertex.

A. Axis of Symmetry: x = 0; Vertex: (0, -5)
B. Axis of Symmetry: x = -3; Vertex: (-3, -5)
C. Axis of Symmetry: x = 5; Vertex: (5, -3)
D. Axis of Symmetry: x = -5; Vertex: (-5, -3)

Answer 1

The axis of symmetry is x = 0 and the vertex is (0, -5) for the given equation y = 3x² - 5.

Step-by-step explanation:

The given equation is y = 3x² - 5.

To find the axis of symmetry, we need to use the formula -b/2a, where a and b are the coefficients of x² and x respectively. In this case, a = 3 and b = 0, so the axis of symmetry is x = 0.

The vertex of the parabola can be found by substituting the value of x from the axis of symmetry into the equation. When x = 0, y = 3(0)² - 5 = 0 - 5 = -5. Therefore, the vertex is (0, -5).