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Find the values for (a,b) so that the equation is true

(a+6) + (3b+1)i = 4+3i

A. (2, 2/3)
B. (-2, 2/3)
C. (-2, 3/2)
D. (10, 2/3)

sos please!

User Austin A
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1 Answer

5 votes

Final answer:

By comparing the real and imaginary parts of the given complex numbers, the values for (a,b) that satisfy the equation are (-2, 2/3).

Therefore, the correct answer is: option B). (-2, 2/3)

Step-by-step explanation:

To find the values for (a,b) so that the equation (a+6) + (3b+1)i = 4+3i is true, we need to compare the real parts and the imaginary parts of the complex numbers on both sides of the equation.

For the real parts, we have a + 6 = 4.

Solving for a, we subtract 6 from both sides to get a = 4 - 6, which simplifies to a = -2.

For the imaginary parts, we have 3b + 1 = 3.

To find b, we subtract 1 from both sides to get 3b = 3 - 1, and then divide by 3 to obtain b = 2/3.

Therefore, the values for (a,b) that make the equation true are (-2, 2/3).

User Olyv
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