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Find the value of k such that (x^3−x^2−kx−36)÷(x+2) has a remainder of zero.

A. k = 6
B. k = 7
C. k = 8
D. k = 9

User Andrew Luo
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Final answer:

To find the value of k such that (x^3−x^2−kx−36)÷(x+2) has a remainder of zero, we can use the remainder theorem. By setting (x+2)=0 and solving for x, we find x=-2. Substituting x=-2 into the polynomial (x^3−x^2−kx−36) and solving for k, we find k=24.

Step-by-step explanation:

To find the value of k such that (x^3−x^2−kx−36)÷(x+2) has a remainder of zero, we need to divide the polynomial (x^3−x^2−kx−36) by (x+2) and find the value of k for which the remainder is zero. To do this, we can use the remainder theorem. According to the remainder theorem, if the polynomial (x^3−x^2−kx−36) divided by (x+2) has a remainder of zero, then (x+2) is a factor of the polynomial.

Therefore, we can set (x+2)=0 and solve for x:

x+2=0

x=-2

Now, substitute x=-2 into the polynomial (x^3−x^2−kx−36) and solve for k:

(-2)^3−(-2)^2−k(-2)−36=0

-8-4+2k-36=0

2k-48=0

2k=48

k=24

Therefore, the value of k such that (x^3−x^2−kx−36)÷(x+2) has a remainder of zero is k=24.

User Domke Consulting
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