Final answer:
The final velocity of the puck is 0 m/s, the acceleration is -0.125 m/s^2, the time it takes to stop is 40 seconds, and it travels 100 meters before stopping.
Step-by-step explanation:
To answer your questions regarding the hockey puck:
a) What is the final velocity of the puck (Vf)?
The final velocity (Vf) of the puck is 0 m/s because it stops after sliding.
b) What is the acceleration of the puck?
To find the acceleration, we can use the formula Vf^2 = Vi^2 + 2a(delta x), where Vi is the initial velocity, a is the acceleration, and delta x is the distance. The equation rearranges to a = (Vf^2 - Vi^2) / (2 * delta x). Substituting the values gives a = (0^2 - 5^2) / (2 * 100) = (-25) / (200) = -0.125 m/s^2. The negative sign indicates the puck is decelerating.
c) What is the time it takes for the puck to stop?
The time (t) can be calculated using the formula Vf = Vi + at. Rearranging for t gives t = (Vf - Vi) / a. By substituting the known values, t = (0 - 5) / (-0.125) = 40 seconds.
d) What is the distance it travels before stopping?
The distance traveled before stopping (delta x) is 100 meters, as given in the question.