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What is the factored form of 1,458x^3 - 2?

a) 2(9x - 1)(81x^2 + 9x + 1)
b) 2(9x + 1)(81x^2 - 9x + 1)
c) (9x - 2)(81x^2 + 18x + 4)
d) (9x + 2)(81x^2 - 18x + 4)

1 Answer

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Final answer:

The factored form of the expression 1,458x^3 - 2 is (9x - 2)(81x^2 + 18x + 4), corresponding to option c.

Step-by-step explanation:

The factored form of the expression 1,458x^3 - 2 is (9x - 2)(81x^2 + 18x + 4), which corresponds to option c. To factor the expression, we first look for any common factors, and in this case there are none. Then, we can look for a common factor in each term, which is 2 in this case.

So we can factor out 2 from each term to get 2(729x^3 - 1). Now we have a difference of cubes, which can be further factored as (9x - 1)(81x^2 + 9x + 1). Therefore, the factored form is (9x - 2)(81x^2 + 18x + 4).

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