Final answer:
To calculate the heat energy required to warm 275 g of water from 76°C to 87°C, use the specific heat capacity of water, which is 4.184 J/g°C, resulting in a required energy of 12,666 J, which does not match the provided options.
Step-by-step explanation:
The heat energy required to warm a substance can be calculated by using the formula:
q = mcΔT, where
q = heat energy (in joules),
m = mass of the substance (in grams),
c = specific heat capacity (in J/g°C),
ΔT = change in temperature (in °C).
For water, the specific heat capacity (c) is 4.184 J/g°C. Given that the mass (m) of the water is 275 g and the temperature change (ΔT) is from 76°C to 87°C, a change of 11°C, we can substitute these values into the formula:
q = (275 g) × (4.184 J/g°C) × (11°C) = 12,666 J, which is not one of the options provided. Thus, there might be an error in the options or the initial data given. However, based on the correct calculation using the provided data, none of the options listed (a) 1925 J, (b) 350 J, (c) 19250 J, (d) 3500 J directly match the calculated value of 12,666 J.