223k views
5 votes
A diver's watch resists an absolute pressure of 5.5 bar. At an ocean having density of

1025 kg/m3 and exposing an atmospheric pressure of 1 bar, what depth can
maximally the diver dive to prevent water inlet into his watch?

User Giulia
by
6.9k points

1 Answer

5 votes

Final answer:

The maximum safe diving depth for a watch with a resistance of 5.5 bar in an ocean with a density of 1025 kg/m3 and an atmospheric pressure of 1 bar is approximately 45 meters.

Step-by-step explanation:

A diver's watch can resist an absolute pressure of 5.5 bar. Given that the density of ocean water is 1025 kg/m3 and atmospheric pressure is 1 bar, we can calculate the maximum depth the diver can safely reach without allowing water into the watch. Pressure due to the water's weight can be calculated as pressure = density × gravitational acceleration × depth (hydrostatic pressure). The additional pressure from the ocean at a certain depth will be equal to the diver's watch resistance (5.5 bar) minus the atmospheric pressure (1 bar). Since 1 bar is approximately equal to the pressure exerted by 10 meters of water depth in the ocean, we can calculate the maximum depth as follows:

Maximum depth = (maximum pressure - atmospheric pressure) × 10 m/bar = (5.5 bar - 1 bar) × 10 m/bar = 45 meters

Thus, the maximum safe diving depth to prevent water from entering the watch would be approximately 45 meters.

User Remy J
by
7.8k points