Question

Karin went to the mall with $ 400; bought a pant, and a jacket that cost

twice as the pant's cost. If she finished the day with $ 25 left, how much
did the jacket cost?

Answer 1

The jacket cost $250.

Step-by-step explanation:

Let's denote the cost of the pant as 'p'. Since the jacket costs twice as much as the pant, we can represent the cost of the jacket as '2p'.

Therefore, the total cost of the pant and jacket is 'p + 2p = 3p'.

Since Karin spent this amount from her initial $400 and finished with $25 left, we can set up the equation: 400 - (3p) = 25.

Solving for 'p': 375 = 3p. Dividing both sides by 3, we find that p = 125.

Hence, the cost of the jacket, which is twice the cost of the pant, is 2p = 2 * 125 = $250.