147k views
2 votes
In a pack of playing cards, two cards are picked one after the other without replacement. What is the probability that the first card is a 2 and the second is a king?

User Fredlahde
by
8.8k points

1 Answer

6 votes

Final answer:

To find the probability of drawing a 2 followed by a king without replacement from a standard deck, we multiply the probability of drawing a 2 (4 out of 52) by the probability of drawing a king after a 2 is drawn (4 out of 51).

Step-by-step explanation:

The question involves calculating the probability of two independent events occurring in sequence when drawing from a standard pack of playing cards without replacement. To find the probability that the first card is a 2 and the second is a king, we multiply the probability of each event occurring separately. There are 4 twos and 4 kings in a standard 52-card deck.

For the first card to be a two: P(2) = 4 out of 52.
For the second card to be a king, after the first card is a 2: P(King | 2) = 4 out of 51, since one card (the 2) has already been removed from the deck.

The combined probability is therefore: P(2 and then King) = P(2) x P(King | 2) = (4/52) x (4/51).

User Jinnlao
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories