Question

For the linear function y = (1/2)x + 1, let's plot ordered pairs for the values in the domain D: {-8, -4, 0, 2, 6}:

A.For x = -8, y = (1/2)(-8) + 1 = -4 + 1 = -3. Ordered pair: (-8, -3)
B.For x = -4, y = (1/2)(-4) + 1 = -2 + 1 = -1. Ordered pair: (-4, -1)
C.For x = 0, y = (1/2)(0) + 1 = 0 + 1 = 1. Ordered pair: (0, 1)
D.For x = 2, y = (1/2)(2) + 1 = 1 + 1 = 2. Ordered pair: (2, 2)
E.For x = 6, y = (1/2)(6) + 1 = 3 + 1 = 4. Ordered pair: (6, 4)

Answer 1

To plot ordered pairs for the given linear function, substitute each x-value into the equation to find its corresponding y-value.

Step-by-step explanation:

To plot ordered pairs for the values in the domain D {-8, -4, 0, 2, 6} for the linear function y = (1/2)x + 1, you can substitute each value of x into the equation to find the corresponding y-value. Let's go through the process step-by-step:

1. For x = -8: y = (1/2)(-8) + 1 = -4 + 1 = -3. Ordered pair: (-8, -3)
2. For x = -4: y = (1/2)(-4) + 1 = -2 + 1 = -1. Ordered pair: (-4, -1)
3. For x = 0: y = (1/2)(0) + 1 = 0 + 1 = 1. Ordered pair: (0, 1)
4. For x = 2: y = (1/2)(2) + 1 = 1 + 1 = 2. Ordered pair: (2, 2)
5. For x = 6: y = (1/2)(6) + 1 = 3 + 1 = 4. Ordered pair: (6, 4)