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Find the equation of the line that is parallel to

Y= -6/7x+3"and passes through the point (-5, 4).

User MarkII
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1 Answer

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Final answer:

The equation of the line that is parallel to y = -6/7x + 3 and passes through the point (-5, 4) is y = -6/7x + 58/7.

Step-by-step explanation:

To find the equation of a line that is parallel to the line y = -6/7x + 3 and passes through the point (-5, 4), we first need to determine the slope of the given line. The slope of the line y = -6/7x + 3 is -6/7. Since a line parallel to the given line will have the same slope, the equation of the parallel line can be written as y = -6/7x + b, where b is the y-intercept of the line. To find the value of b, we substitute the coordinates of the given point into the equation and solve for b:

4 = (-6/7)(-5) + b

b = 4 + 30/7 = 58/7.

Therefore, the equation of the line that is parallel to y = -6/7x + 3 and passes through the point (-5, 4) is y = -6/7x + 58/7.

User Tamarabyte
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