7.4k views
5 votes
If the random variable X has a mean of mu and a standard deviation of sigma, then (x-I)/o Has a mean and standard deviation respectively

User Nizzle
by
8.2k points

1 Answer

5 votes

Final answer:

The transformed random variable Z = (X - μ) / σ has a mean of 0 and a standard deviation of 1, resulting in a standard normal distribution known as z-score.

Step-by-step explanation:

If the random variable X has a mean of μ (mu) and a standard deviation of σ (sigma), then the transformed random variable Z = (X - μ) / σ has a mean and standard deviation, respectively. Applying the transformation to X standardizes it, resulting in a standard normal distribution with a mean of 0 and a standard deviation of 1. This is because any number subtracted by itself is 0 (which is what happens to the mean in the numerator), and any number divided by itself is 1 (which is the case for the standard deviation in the denominator). The transformation is commonly referred to as calculating the z-score, which allows us to compare data from different normal distributions.

User Gannet
by
8.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories