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How many moles of NaCl are present in a 0.6 L solution that has a molarity of 1.55M

User Hbin
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1 Answer

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Step-by-step explanation:

The molarity of a solution is defined like the number of moles of solute per liters of solution.

Molarity = moles of solute/(volume of solution in L)

We have to find the number of moles of NaCl that are present in 0.6 L of a 1.55 M solution. So we know the volume in liters and the molarity of the solution. We can solve the formula for the number of moles of NaCl and get the answer to our problem.

molarity = 1.55 M

volume of solution = 0.6 L

molarity = moles of NaCl/volume of solution

moles of NaCl = molarity * volume of solution

moles of NaCl = 1.55 M * 0.6 L

moles of NaCl = 0.93 moles

Answer: there are 0.93 moles of NaCl present in the solution.

User Naeem Ibrahim
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